{"id":964,"date":"2025-09-30T12:16:01","date_gmt":"2025-09-30T10:16:01","guid":{"rendered":"https:\/\/biophy-sympa.com\/?page_id=964"},"modified":"2025-09-30T13:04:25","modified_gmt":"2025-09-30T11:04:25","slug":"bases-de-la-radioactivite-3-3-exercices-n1-a-4","status":"publish","type":"page","link":"https:\/\/biophy-sympa.com\/index.php\/bases-de-la-radioactivite-3-3-exercices-n1-a-4\/","title":{"rendered":"Bases de la Radioactivit\u00e9 3\/3 : Exercices n\u00b01 \u00e0 4"},"content":{"rendered":"<p>[et_pb_section fb_built=&#8221;1&#8243; _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_row _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_column type=&#8221;4_4&#8243; _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; global_colors_info=&#8221;{}&#8221;][et_pb_text _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; text_font=&#8221;Libre Baskerville||||||||&#8221; text_font_size=&#8221;22px&#8221; custom_margin=&#8221;||33px|||&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<p>Question n\u00b01 \u00e0 4 :<\/p>\n<p>[\/et_pb_text][et_pb_text _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; text_font=&#8221;Libre Baskerville||||||||&#8221; custom_margin=&#8221;||35px|||&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<p>Les quarte questions se rapportent au sch\u00e9ma de d\u00e9sint\u00e9gration suivant. Il n&#8217;y a qu&#8217;une seule r\u00e9ponse correcte pour chacune d&#8217;entre elles.<\/p>\n<p>[\/et_pb_text][et_pb_image src=&#8221;https:\/\/biophy-sympa.com\/wp-content\/uploads\/2025\/09\/Schema-de-desintegration-2.png&#8221; align=&#8221;center&#8221; _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; width=&#8221;20%&#8221; animation_style=&#8221;zoom&#8221; hover_enabled=&#8221;0&#8243; global_colors_info=&#8221;{}&#8221; width_last_edited=&#8221;on|tablet&#8221; sticky_enabled=&#8221;0&#8243; width_phone=&#8221;51%&#8221; width_tablet=&#8221;36%&#8221;][\/et_pb_image][et_pb_text _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; text_font=&#8221;Libre Baskerville||||||||&#8221; custom_margin=&#8221;||35px|||&#8221; custom_padding=&#8221;||2px|||&#8221; animation_style=&#8221;slide&#8221; animation_direction=&#8221;left&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<\/p>\n<p>On donne les d\u00e9fauts de masses des noyaux :<\/p>\n<p>|\u2206MK(38,19)| = 28,786 MeV\/c<span style=\"font-size: x-small;\"><sup>2<\/sup><\/span>\u00a0<\/p>\n<p>|\u2206MAr(38,18)| = 34,718 MeV\/c<span style=\"font-size: x-small;\"><sup>2<\/sup><\/span><\/p>\n<p>[\/et_pb_text][et_pb_code _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; animation_style=&#8221;bounce&#8221; animation_direction=&#8221;bottom&#8221; global_colors_info=&#8221;{}&#8221;]<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-19\" class=\"h5p-iframe\" data-content-id=\"19\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q1\"><\/iframe><\/div><!-- [et_pb_line_break_holder] -->[\/et_pb_code][et_pb_code _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; animation_style=&#8221;flip&#8221; global_colors_info=&#8221;{}&#8221;]<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-20\" class=\"h5p-iframe\" data-content-id=\"20\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q2\"><\/iframe><\/div>[\/et_pb_code][et_pb_code _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; animation_style=&#8221;zoom&#8221; hover_enabled=&#8221;0&#8243; global_colors_info=&#8221;{}&#8221; sticky_enabled=&#8221;0&#8243;]<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-21\" class=\"h5p-iframe\" data-content-id=\"21\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q3\"><\/iframe><\/div>[\/et_pb_code][et_pb_code _builder_version=&#8221;4.27.4&#8243; _module_preset=&#8221;default&#8221; animation_style=&#8221;flip&#8221; locked=&#8221;off&#8221; global_colors_info=&#8221;{}&#8221;]<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-22\" class=\"h5p-iframe\" data-content-id=\"22\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 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de d\u00e9sint\u00e9gration suivant. Il n&#8217;y a qu&#8217;une seule r\u00e9ponse correcte pour chacune d&#8217;entre elles.On donne les d\u00e9fauts de masses des noyaux : |\u2206MK(38,19)| = 28,786 MeV\/c2\u00a0 |\u2206MAr(38,18)| = 34,718 MeV\/c2<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-19\" class=\"h5p-iframe\" data-content-id=\"19\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q1\"><\/iframe><\/div><div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-20\" class=\"h5p-iframe\" data-content-id=\"20\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q2\"><\/iframe><\/div><div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-21\" class=\"h5p-iframe\" data-content-id=\"21\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"BR 3\/3 Q3\"><\/iframe><\/div><div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-22\" class=\"h5p-iframe\" data-content-id=\"22\" 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